(5*x-2)^2-(4-5*x)^2=x*(3*x+1)-3*(x-1)*(x+3)+4

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Solution for (5*x-2)^2-(4-5*x)^2=x*(3*x+1)-3*(x-1)*(x+3)+4 equation: 



(5x-2)^2-(4-5x)^2=x(3x+1)-3(x-1)(x+3)+4

We move all terms to the left:

(5x-2)^2-(4-5x)^2-(x(3x+1)-3(x-1)(x+3)+4)=0

We add all the numbers together, and all the variables

(5x-2)^2-(-5x+4)^2-(x(3x+1)-3(x-1)(x+3)+4)=0

We multiply parentheses ..

-(x(3x+1)-3(+x^2+3x-1x-3)+4)+(5x-2)^2-(-5x+4)^2=0



We calculate terms in parentheses: -(x(3x+1)-3(+x^2+3x-1x-3)+4), so:

x(3x+1)-3(+x^2+3x-1x-3)+4

determiningTheFunctionDomain
-3(+x^2+3x-1x-3)+x(3x+1)+4

We multiply parentheses

-3x^2+3x^2-9x+3x+x+9+4

We add all the numbers together, and all the variables

-5x+13

Back to the equation:

-(-5x+13)



We get rid of parentheses

5x+(5x-2)^2-(-5x+4)^2-13=0

We move all terms containing x to the left, all other terms to the right

5x+(5x-2)^2-(-5x+4)^2=13

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